Webreturn typeid (object) ; } And to call it obj->get_type (myObj); yes, you can. remember though that the type of the variable object is a pointer and this would give you the type of … WebApr 7, 2024 · Args, typename = typename std::enable_if...>::value>::type> void text(Args &&...args) { push(std::make_shared(std::forward(args)...)); } private: std::weak_ptr …

c++ - How do I get the type of a variable? - Stack Overflow

WebJan 17, 2012 · In c++ to get type of data we can use typeid but it's give you the data as const char*,and i want it to return the type of the data. Example: int data = 20 ; float … WebMar 23, 2024 · The typeid (obj).name () thing always gives the type of the variable as it was declared, not the actual type (class) of the object. If the variable obj is assigned to an … stanford university rea acceptance rate

C++ Type Erasure on the Stack - Part III

WebSep 28, 2016 · The get the name of a class you can use overloading of a template class, then you just need to implement a partial specialization of this class for each type you … WebAug 25, 2016 · There is a typeid operator, which returns an instance of std::type_info, with which you can get the name of the type. Not sure if that will help you though. First, the … WebThere are two key concepts needed to understand the description of typename, and they are qualifiedand dependentnames. Qualified and unqualified names A qualified name is one that specifies a scope. the following C++ program, the references to coutand endlare qualified names: #include int main() { std::cout "Hello world!" std::endl; stanford university qb